We have the following table :<img src="https://lightyellow-stork-291267.hostingersite.com/wp-content/uploads/2025/11/Screenshot_489_DJqpFlV.png" alt="Screenshot_489">o10 is given to Elise and o9 is given to Bharat .Now as Elise values his own bundle at an even number so the only two objects which can be given to Elise is o1 or o5 or o7.Case 1 :o1 is given to EliseNow the total valuation of Elise = 12Valuation of Disha is an odd numberSo we can say Amar , Bharat and Charles values their bundles at 16 .So for Bharat the valuation to be 16, o7 will be given to himso we getBharat - o9 and o7 and Elise -o10 and o1For charles to have valuation 16the only way = 8+8so we can say o8 is given to charles along with either o2 or o3 .(o1 and o8 cannot be together )Now for Amart to have a valuation of 16the only way possible = 9+7Now so we can sayAmar will receive either o2 or o3 and o5 .Now we are left with 04 and o6So if Disha receives o4 and o6The valuation of Disha will be 5+3 =8 which is not an odd numberso this case is discarded. Case 2 Elise receives o5 or o7 .Now Valuation of Elise = 16 .And Elise receives o10 and o5/o7.Bharat received o9 and we know the evaluation of Bharat is an even number and the minimum even number possible for valuation of Bharat is 16 and no one can have evaluation more than 16 so Bharat received o7 .So Elise received o5 .So we haveBharat - o9 ,o7Elise -o10,o5.Now as we know o1 ,o2 and o3 are given to three different persons so they are Amar, Charles and Disha .Now As per Amarhe values Bharat at 17 so he envy himSo Amar will value his bundle less than 16So the only possibility for Amar to value his bundle less than 16 = 12 =9+3.Now we can say Charu will have 16 as his own valuation so he will get 8+8 .Now o8 will be given to Charu, and he cannot have o1 , also he cannot have o2 because if he has o2 he will value Bharat’s bundle as 17 and will envy him which is not possible so Charu will have o3,o8Now Amar will have o2 and Disha will have o1.Now Amar will not have o4 because in that case Charles will envy Amar and is not possible so we can say Amar will have o6 and Disha will have o4.So we have the following : Amar - o2,o6Bharat -o9,o7Charu -o3,o8Disha o1,o4Elise -o10,o5So o8 is given to Charu.

We have the following table :<img src="https://lightyellow-stork-291267.hostingersite.com/wp-content/uploads/2025/11/Screenshot_489_DJqpFlV.png" alt="Screenshot_489">o10 is given to Elise and o9 is given to Bharat .Now as Elise values his own bundle at an even number so the only two objects which can be given to Elise is o1 or o5 or o7.Case 1 :o1 is given to EliseNow the total valuation of Elise = 12Valuation of Disha is an odd numberSo we can say Amar , Bharat and Charles values their bundles at 16 .So for Bharat the valuation to be 16, o7 will be given to himso we getBharat - o9 and o7 and Elise -o10 and o1For charles to have valuation 16the only way = 8+8so we can say o8 is given to charles along with either o2 or o3 .(o1 and o8 cannot be together )Now for Amart to have a valuation of 16the only way possible = 9+7Now so we can sayAmar will receive either o2 or o3 and o5 .Now we are left with 04 and o6So if Disha receives o4 and o6The valuation of Disha will be 5+3 =8 which is not an odd numberso this case is discarded. Case 2 Elise receives o5 or o7 .Now Valuation of Elise = 16 .And Elise receives o10 and o5/o7.Bharat received o9 and we know the evaluation of Bharat is an even number and the minimum even number possible for valuation of Bharat is 16 and no one can have evaluation more than 16 so Bharat received o7 .So Elise received o5 .So we haveBharat - o9 ,o7Elise -o10,o5.Now as we know o1 ,o2 and o3 are given to three different persons so they are Amar, Charles and Disha .Now As per Amarhe values Bharat at 17 so he envy himSo Amar will value his bundle less than 16So the only possibility for Amar to value his bundle less than 16 = 12 =9+3.Now we can say Charu will have 16 as his own valuation so he will get 8+8 .Now o8 will be given to Charu, and he cannot have o1 , also he cannot have o2 because if he has o2 he will value Bharat’s bundle as 17 and will envy him which is not possible so Charu will have o3,o8Now Amar will have o2 and Disha will have o1.Now Amar will not have o4 because in that case Charles will envy Amar and is not possible so we can say Amar will have o6 and Disha will have o4.So we have the following : Amar - o2,o6Bharat -o9,o7Charu -o3,o8Disha o1,o4Elise -o10,o5So Amar envies someone else

We have the following table :<img src="https://lightyellow-stork-291267.hostingersite.com/wp-content/uploads/2025/11/Screenshot_489_DJqpFlV.png" alt="Screenshot_489">o10 is given to Elise and o9 is given to Bharat .Now as Elise values his own bundle at an even number so the only two objects which can be given to Elise is o1 or o5 or o7.Case 1 :o1 is given to EliseNow the total valuation of Elise = 12Valuation of Disha is an odd numberSo we can say Amar , Bharat and Charles values their bundles at 16 .So for Bharat the valuation to be 16, o7 will be given to himso we getBharat - o9 and o7 and Elise -o10 and o1For charles to have valuation 16the only way = 8+8so we can say o8 is given to charles along with either o2 or o3 .(o1 and o8 cannot be together )Now for Amart to have a valuation of 16the only way possible = 9+7Now so we can sayAmar will receive either o2 or o3 and o5 .Now we are left with 04 and o6So if Disha receives o4 and o6The valuation of Disha will be 5+3 =8 which is not an odd numberso this case is discarded. Case 2 Elise receives o5 or o7 .Now Valuation of Elise = 16 .And Elise receives o10 and o5/o7.Bharat received o9 and we know the evaluation of Bharat is an even number and the minimum even number possible for valuation of Bharat is 16 and no one can have evaluation more than 16 so Bharat received o7 .So Elise received o5 .So we haveBharat - o9 ,o7Elise -o10,o5.Now as we know o1 ,o2 and o3 are given to three different persons so they are Amar, Charles and Disha .Now As per Amarhe values Bharat at 17 so he envy himSo Amar will value his bundle less than 16So the only possibility for Amar to value his bundle less than 16 = 12 =9+3.Now we can say Charu will have 16 as his own valuation so he will get 8+8 .Now o8 will be given to Charu, and he cannot have o1 , also he cannot have o2 because if he has o2 he will value Bharat’s bundle as 17 and will envy him which is not possible so Charu will have o3,o8Now Amar will have o2 and Disha will have o1.Now Amar will not have o4 because in that case Charles will envy Amar and is not possible so we can say Amar will have o6 and Disha will have o4.So we have the following : Amar - o2,o6Bharat -o9,o7Charu -o3,o8Disha o1,o4Elise -o10,o5Amar's own valuation = 9+3 =12

We have the following table :<img src="https://lightyellow-stork-291267.hostingersite.com/wp-content/uploads/2025/11/Screenshot_489_DJqpFlV.png" alt="Screenshot_489">o10 is given to Elise and o9 is given to Bharat .Now as Elise values his own bundle at an even number so the only two objects which can be given to Elise is o1 or o5 or o7.Case 1 :o1 is given to EliseNow the total valuation of Elise = 12Valuation of Disha is an odd numberSo we can say Amar , Bharat and Charles values their bundles at 16 .So for Bharat the valuation to be 16, o7 will be given to himso we getBharat - o9 and o7 and Elise -o10 and o1For charles to have valuation 16the only way = 8+8so we can say o8 is given to charles along with either o2 or o3 .(o1 and o8 cannot be together )Now for Amart to have a valuation of 16the only way possible = 9+7Now so we can sayAmar will receive either o2 or o3 and o5 .Now we are left with 04 and o6So if Disha receives o4 and o6The valuation of Disha will be 5+3 =8 which is not an odd numberso this case is discarded. Case 2 Elise receives o5 or o7 .Now Valuation of Elise = 16 .And Elise receives o10 and o5/o7.Bharat received o9 and we know the evaluation of Bharat is an even number and the minimum even number possible for valuation of Bharat is 16 and no one can have evaluation more than 16 so Bharat received o7 .So Elise received o5 .So we haveBharat - o9 ,o7Elise -o10,o5.Now as we know o1 ,o2 and o3 are given to three different persons so they are Amar, Charles and Disha .Now As per Amarhe values Bharat at 17 so he envy himSo Amar will value his bundle less than 16So the only possibility for Amar to value his bundle less than 16 = 12 =9+3.Now we can say Charu will have 16 as his own valuation so he will get 8+8 .Now o8 will be given to Charu, and he cannot have o1 , also he cannot have o2 because if he has o2 he will value Bharat’s bundle as 17 and will envy him which is not possible so Charu will have o3,o8Now Amar will have o2 and Disha will have o1.Now Amar will not have o4 because in that case Charles will envy Amar and is not possible so we can say Amar will have o6 and Disha will have o4.So we have the following : Amar - o2,o6Bharat -o9,o7Charu -o3,o8Disha o1,o4Elise -o10,o5o4 is given to Disha

We have the following table :<img src="https://lightyellow-stork-291267.hostingersite.com/wp-content/uploads/2025/11/Screenshot_489_DJqpFlV.png" alt="Screenshot_489">o10 is given to Elise and o9 is given to Bharat .Now as Elise values his own bundle at an even number so the only two objects which can be given to Elise is o1 or o5 or o7.Case 1 :o1 is given to EliseNow the total valuation of Elise = 12Valuation of Disha is an odd numberSo we can say Amar , Bharat and Charles values their bundles at 16 .So for Bharat the valuation to be 16, o7 will be given to himso we getBharat - o9 and o7 and Elise -o10 and o1For charles to have valuation 16the only way = 8+8so we can say o8 is given to charles along with either o2 or o3 .(o1 and o8 cannot be together )Now for Amart to have a valuation of 16the only way possible = 9+7Now so we can sayAmar will receive either o2 or o3 and o5 .Now we are left with 04 and o6So if Disha receives o4 and o6The valuation of Disha will be 5+3 =8 which is not an odd numberso this case is discarded. Case 2 Elise receives o5 or o7 .Now Valuation of Elise = 16 .And Elise receives o10 and o5/o7.Bharat received o9 and we know the evaluation of Bharat is an even number and the minimum even number possible for valuation of Bharat is 16 and no one can have evaluation more than 16 so Bharat received o7 .So Elise received o5 .So we haveBharat - o9 ,o7Elise -o10,o5.Now as we know o1 ,o2 and o3 are given to three different persons so they are Amar, Charles and Disha .Now As per Amarhe values Bharat at 17 so he envy himSo Amar will value his bundle less than 16So the only possibility for Amar to value his bundle less than 16 = 12 =9+3.Now we can say Charu will have 16 as his own valuation so he will get 8+8 .Now o8 will be given to Charu, and he cannot have o1 , also he cannot have o2 because if he has o2 he will value Bharat’s bundle as 17 and will envy him which is not possible so Charu will have o3,o8Now Amar will have o2 and Disha will have o1.Now Amar will not have o4 because in that case Charles will envy Amar and is not possible so we can say Amar will have o6 and Disha will have o4.So we have the following : Amar - o2,o6Bharat -o9,o7Charu -o3,o8Disha o1,o4Elise -o10,o5o5 is given to Elise

We have the following table :<img src="https://lightyellow-stork-291267.hostingersite.com/wp-content/uploads/2025/11/Screenshot_489_DJqpFlV.png" alt="Screenshot_489">o10 is given to Elise and o9 is given to Bharat .Now as Elise values his own bundle at an even number so the only two objects which can be given to Elise is o1 or o5 or o7.Case 1 :o1 is given to EliseNow the total valuation of Elise = 12Valuation of Disha is an odd numberSo we can say Amar , Bharat and Charles values their bundles at 16 .So for Bharat the valuation to be 16, o7 will be given to himso we getBharat - o9 and o7 and Elise -o10 and o1For charles to have valuation 16the only way = 8+8so we can say o8 is given to charles along with either o2 or o3 .(o1 and o8 cannot be together )Now for Amart to have a valuation of 16the only way possible = 9+7Now so we can sayAmar will receive either o2 or o3 and o5 .Now we are left with 04 and o6So if Disha receives o4 and o6The valuation of Disha will be 5+3 =8 which is not an odd numberso this case is discarded. Case 2 Elise receives o5 or o7 .Now Valuation of Elise = 16 .And Elise receives o10 and o5/o7.Bharat received o9 and we know the evaluation of Bharat is an even number and the minimum even number possible for valuation of Bharat is 16 and no one can have evaluation more than 16 so Bharat received o7 .So Elise received o5 .So we haveBharat - o9 ,o7Elise -o10,o5.Now as we know o1 ,o2 and o3 are given to three different persons so they are Amar, Charles and Disha .Now As per Amarhe values Bharat at 17 so he envy himSo Amar will value his bundle less than 16So the only possibility for Amar to value his bundle less than 16 = 12 =9+3.Now we can say Charu will have 16 as his own valuation so he will get 8+8 .Now o8 will be given to Charu, and he cannot have o1 , also he cannot have o2 because if he has o2 he will value Bharat’s bundle as 17 and will envy him which is not possible so Charu will have o3,o8Now Amar will have o2 and Disha will have o1.Now Amar will not have o4 because in that case Charles will envy Amar and is not possible so we can say Amar will have o6 and Disha will have o4.So we have the following : Amar - o2,o6Bharat -o9,o7Charu -o3,o8Disha o1,o4Elise -o10,o5So o1 is given to Disha

Accumulating all the data :&nbsp;We get the following table :<img src="https://lightyellow-stork-291267.hostingersite.com/wp-content/uploads/2025/11/image_pCh9MpQ.png">Note a-b : represents the duration where a is the day when order is booked and b is the day when it is dispatched .Now No booking days from the table are : September 8,9,10,11,12 and 14.So a total of 6 days .

Accumulating all the data :We get the following table :<img src="https://lightyellow-stork-291267.hostingersite.com/wp-content/uploads/2025/11/image_pCh9MpQ.png">Note a-b : represents the duration where a is the day when order is booked and b is the day when it is dispatched .Now Envelopes and Accessories has only 1 ship mode i.e Standard class .So therefore processing days for envelopes = 7-3 =4&nbsp;and processing days for accessories = 19-1 =18&nbsp;Therefore average =&nbsp;(18+4)/2=11

Accumulating all the data :We get the following table :<img src="https://lightyellow-stork-291267.hostingersite.com/wp-content/uploads/2025/11/image_pCh9MpQ.png">Note a-b : represents the duration where a is the day when order is booked and b is the day when it is dispatched .Now taking average processing time per order for the above mentioned categories we get :Art =(2+8+2+1+7)/5&nbsp;&nbsp;=4Binders =(1+1+11+2)/4&nbsp;&nbsp;=3.75Papers =&nbsp;(3+2+5)/3&nbsp;&nbsp;=3.33Phones =(2+12+1)/3&nbsp;&nbsp;=5So in decreasing order we get Phones , Art ,Binder , Paper.

Accumulating all the data :We get the following table :<img src="https://lightyellow-stork-291267.hostingersite.com/wp-content/uploads/2025/11/image_pCh9MpQ.png">Note a-b : represents the duration where a is the day when order is booked and b is the day when it is dispatched .Now from the table we observe that the total number of orders are 35 and 7 orders have a processing time of 1 unit&nbsp;The 7 orders are : Arts Standard class,Binders First class and standard class, Phones First class, Bookcases second class ( 2 orders)&nbsp;and Chairs standard class.So the percentage =&nbsp;7/35×&nbsp;100&nbsp;=&nbsp;20

Group A :Since Aruna played 3 games if she belongs to rank 2 or rank 3 in her group she must have reached the semifinals and lost in the semifinals. But for this case, she must play against rank 1 and rank 3 in her group. But she did not play against Arif from her group.Hence Aruna was ranked 1 in her group, Among Azul and Arif one of them was ranked 2 and the other was ranked 3. Azul defeated Arif in the first round and in the second round lost to Aruna. Aruna played her first round with Azul and won the round and played against the winner from group B and defeated them and moved to the finals.Group B :Brij did not play against Brinda. Biju played three games, Brij and Brinda played one game each.Since Brij and Brinda played only one game each one of them was ranked 1 and the other was ranked 2 and 3. Brij did not play against Brinda. We are aware that Aruna reached finals and hence the person from Group B did not reach the finals. Biju played three games and hence must have played with Brij/Brinda in the first round and won the round. Plays with Brij/ Brinda and wins the second round. Plays with Aruna and loses the third round.<img src="https://lightyellow-stork-291267.hostingersite.com/wp-content/uploads/2025/11/image_zcEdsHx1.png" alt="image_zcEdsHx(1)">Group - C :Chitra played 2 matches and Chetan played 2 matches. For Chitra to play 2 matches if she is rank 2 or rank 3 in her group. She must at least reach the semifinals. But in this case, Chetan will be defeated in his first round. So Chitra must be ranked 1 in her group and Chetan must be ranked 2 or rank 3 in his group. He defeats Chhavi in his first round and loses to Chitra in his second round. Chitra plays Chetan in her first round, wins over the winner of group D in her second round, and loses in the final against Aruna as per condition 1.Group -D :The person from Group D did not reach the finals because Chitra reached the finals. In order for Dipen to play 3 matches before his finals. Dipen must be ranked 2 or rank 3 in his group and plays Deb and Donna in the first two rounds in any order and wins over both of them. Dipen loses to Chitra in his third round.<img src="https://lightyellow-stork-291267.hostingersite.com/wp-content/uploads/2025/11/image_xR991FO.png" alt="image">Aruna plays Chitra in the finals and wins the final round.Dipen was ranked 2 or 3 in his group

Group A :Since Aruna played 3 games if she belongs to rank 2 or rank 3 in her group she must have reached the semifinals and lost in the semifinals. But for this case, she must play against rank 1 and rank 3 in her group. But she did not play against Arif from her group.Hence Aruna was ranked 1 in her group, Among Azul and Arif one of them was ranked 2 and the other was ranked 3. Azul defeated Arif in the first round and in the second round lost to Aruna. Aruna played her first round with Azul and won the round and played against the winner from group B and defeated them and moved to the finals.Group B :Brij did not play against Brinda. Biju played three games, Brij and Brinda played one game each.Since Brij and Brinda played only one game each one of them was ranked 1 and the other was ranked 2 and 3. Brij did not play against Brinda. We are aware that Aruna reached finals and hence the person from Group B did not reach the finals. Biju played three games and hence must have played with Brij/Brinda in the first round and won the round. Plays with Brij/ Brinda and wins the second round. Plays with Aruna and loses the third round.<img src="https://lightyellow-stork-291267.hostingersite.com/wp-content/uploads/2025/11/image_zcEdsHx1.png" alt="image_zcEdsHx(1)">Group - C :Chitra played 2 matches and Chetan played 2 matches. For Chitra to play 2 matches if she is rank 2 or rank 3 in her group. She must at least reach the semifinals. But in this case, Chetan will be defeated in his first round. So Chitra must be ranked 1 in her group and Chetan must be ranked 2 or rank 3 in his group. He defeats Chhavi in his first round and loses to Chitra in his second round. Chitra plays Chetan in her first round, wins over the winner of group D in her second round, and loses in the final against Aruna as per condition 1.Group -D :The person from Group D did not reach the finals because Chitra reached the finals. In order for Dipen to play 3 matches before his finals. Dipen must be ranked 2 or rank 3 in his group and plays Deb and Donna in the first two rounds in any order and wins over both of them. Dipen loses to Chitra in his third round.<img src="https://lightyellow-stork-291267.hostingersite.com/wp-content/uploads/2025/11/image_xR991FO.png" alt="image">Aruna plays Chitra in the finals and wins the final round.Chitra and Dipen played in the semifinals

Group A :Since Aruna played 3 games if she belongs to rank 2 or rank 3 in her group she must have reached the semifinals and lost in the semifinals. But for this case, she must play against rank 1 and rank 3 in her group. But she did not play against Arif from her group.Hence Aruna was ranked 1 in her group, Among Azul and Arif one of them was ranked 2 and the other was ranked 3. Azul defeated Arif in the first round and in the second round lost to Aruna. Aruna played her first round with Azul and won the round and played against the winner from group B and defeated them and moved to the finals.Group B :Brij did not play against Brinda. Biju played three games, Brij and Brinda played one game each.Since Brij and Brinda played only one game each one of them was ranked 1 and the other was ranked 2 and 3. Brij did not play against Brinda. We are aware that Aruna reached finals and hence the person from Group B did not reach the finals. Biju played three games and hence must have played with Brij/Brinda in the first round and won the round. Plays with Brij/ Brinda and wins the second round. Plays with Aruna and loses the third round.<img src="https://lightyellow-stork-291267.hostingersite.com/wp-content/uploads/2025/11/image_zcEdsHx1.png" alt="image_zcEdsHx(1)">Group - C :Chitra played 2 matches and Chetan played 2 matches. For Chitra to play 2 matches if she is rank 2 or rank 3 in her group. She must at least reach the semifinals. But in this case, Chetan will be defeated in his first round. So Chitra must be ranked 1 in her group and Chetan must be ranked 2 or rank 3 in his group. He defeats Chhavi in his first round and loses to Chitra in his second round. Chitra plays Chetan in her first round, wins over the winner of group D in her second round, and loses in the final against Aruna as per condition 1.Group -D :The person from Group D did not reach the finals because Chitra reached the finals. In order for Dipen to play 3 matches before his finals. Dipen must be ranked 2 or rank 3 in his group and plays Deb and Donna in the first two rounds in any order and wins over both of them. Dipen loses to Chitra in his third round.<img src="https://lightyellow-stork-291267.hostingersite.com/wp-content/uploads/2025/11/image_xR991FO.png" alt="image">Aruna plays Chitra in the finals and wins the final round.Aruna is the winner.

Group A :Since Aruna played 3 games if she belongs to rank 2 or rank 3 in her group she must have reached the semifinals and lost in the semifinals. But for this case, she must play against rank 1 and rank 3 in her group. But she did not play against Arif from her group.Hence Aruna was ranked 1 in her group, Among Azul and Arif one of them was ranked 2 and the other was ranked 3. Azul defeated Arif in the first round and in the second round lost to Aruna. Aruna played her first round with Azul and won the round and played against the winner from group B and defeated them and moved to the finals.Group B :Brij did not play against Brinda. Biju played three games, Brij and Brinda played one game each.Since Brij and Brinda played only one game each one of them was ranked 1 and the other was ranked 2 and 3. Brij did not play against Brinda. We are aware that Aruna reached finals and hence the person from Group B did not reach the finals. Biju played three games and hence must have played with Brij/Brinda in the first round and won the round. Plays with Brij/ Brinda and wins the second round. Plays with Aruna and loses the third round.<img src="https://lightyellow-stork-291267.hostingersite.com/wp-content/uploads/2025/11/image_zcEdsHx1.png" alt="image_zcEdsHx(1)">Group - C :Chitra played 2 matches and Chetan played 2 matches. For Chitra to play 2 matches if she is rank 2 or rank 3 in her group. She must at least reach the semifinals. But in this case, Chetan will be defeated in his first round. So Chitra must be ranked 1 in her group and Chetan must be ranked 2 or rank 3 in his group. He defeats Chhavi in his first round and loses to Chitra in his second round. Chitra plays Chetan in her first round, wins over the winner of group D in her second round, and loses in the final against Aruna as per condition 1.Group -D :The person from Group D did not reach the finals because Chitra reached the finals. In order for Dipen to play 3 matches before his finals. Dipen must be ranked 2 or rank 3 in his group and plays Deb and Donna in the first two rounds in any order and wins over both of them. Dipen loses to Chitra in his third round.<img src="https://lightyellow-stork-291267.hostingersite.com/wp-content/uploads/2025/11/image_xR991FO.png" alt="image">Aruna plays Chitra in the finals and wins the final round.Brij was the player from group B who played Chitra. Aruna played in finals, Chetan in round 2, and Dipen in semi finals

Using condition 1 :Ravi had a total of 21 points in timeliness. 3 of the four customers among Atal, Bihari, Chirag, and Deepak gave him the same ratings. Atal gave the highest rating in timeliness in comparison with Bihari and Chirag. Hence he must have given the distinct rating.Using condition 2 :The possibilities are A - 9, B - 4, C - 4, D - 4.A - 6, B - 5, C - 5, D - 5.Ravi received a total of 29 points in the Packaging and for this, the possibility of the four scores are (5, 7, 8, 9) awarded by the four customers.In Hygiene the sum of the ratings awarded was 26. This could possibly be awarded by considering the following cases :A-(4,6,7,9) , B-( 5,6,7,8), C-(4,5,8,9).Using condition 4: Bihari gave the highest rating in packaging and thus Bihari must have given a 9 rating in the packaging.Chirag gave the highest rating in Hygiene. In condition 3 it was mentioned that Chirag gave the same points for packaging and hygiene. Since 9 was rated by Bihari packaging it cannot be awarded by Chirag in packaging and hygiene. Since Chirag was awarded the highest in Hygiene. He must award 8 points in Hygiene and Packaging.Hence of the three possibilities among A, B, and C for Hygiene&nbsp;only B is the possible case with 8 as the maximum score.In condition 5 it was mentioned that everyone awarded Ravi between 5 and 7 in Behaviour. Unique maximum and minimum ratings in this parameter were given by Atal and Deepak respectively.Hence Atal must have awarded 7, Deepak 6, Bihari, and Chirag 6 each in Behaviour.The two possible cases are :Case 1 :<img src="https://lightyellow-stork-291267.hostingersite.com/wp-content/uploads/2025/11/image_Z5OM6BV.png" alt="image">Case 2 :<img src="https://lightyellow-stork-291267.hostingersite.com/wp-content/uploads/2025/11/image_DOQJCva.png" alt="image">The ratings awarded by Atal and Deepak in Packaging are among 5 and 7.The ratings awarded by Atal, Bihari, Deepak are among 5,6, and 7.Atal individual ranking in Packaging and Hygiene are the same. The same is true for Deepak.Since Atal and Deepak can give the ranking among 3 and 4 in Packaging as Bihari is first and Chirag is second in this parameter.They can rank 3 or 4 in the Hygiene parameter also. Hence Bihari must rate 7 points in Hygiene.In both the possibilities Bihari and Chirag award a total of 26 points. Hence he wins 40 because the total ratings are greater than 25 received from Bihari and Chirag.Since he gets a total of 120 in bonuses and tips. He must have 80 from Atal and Deepak.This is possible if he gets a tip of 30 ad 50 from them respectively.In case 1 irrespective of Atal standing at rank 3 or rank 4 in Hygiene and Packaging Atal total rating is greater than 25 which implies Ravi gets a tip from Atal but this is not a possible case because Ravi needs a total of Rs 80 from Atal and Deepak. From Atal if he gets Rs 20 as a bonus he cannot get a total of Rs 120 and hence this case fails.Hence case 1 fails.In case 2 there are two possibilities :Atal ranking 3 in both the parameters and Deepak 4th. Atal ranking 4th in both the parameters and Deepak 3rdIn the case where Atal ranks 3rd in Packaging and Hygiene the total score is 26 and is not a feasible case.Case - 2A<img src="https://lightyellow-stork-291267.hostingersite.com/wp-content/uploads/2025/11/image_WKcIuOa.png" alt="image">Case - 2B :<img src="https://lightyellow-stork-291267.hostingersite.com/wp-content/uploads/2025/11/image_Y6yaVvF.png" alt="image">Case - 2A&nbsp;fails because Atal's total rating is greater than 25 which should not be the case.The minimum rating awarded is 5.

Using condition 1 :Ravi had a total of 21 points in timeliness. 3 of the four customers among Atal, Bihari, Chirag, and Deepak gave him the same ratings. Atal gave the highest rating in timeliness in comparison with Bihari and Chirag. Hence he must have given the distinct rating.Using condition 2 :The possibilities are A - 9, B - 4, C - 4, D - 4.A - 6, B - 5, C - 5, D - 5.Ravi received a total of 29 points in the Packaging and for this, the possibility of the four scores are (5, 7, 8, 9) awarded by the four customers.In Hygiene the sum of the ratings awarded was 26. This could possibly be awarded by considering the following cases :A-(4,6,7,9) , B-( 5,6,7,8), C-(4,5,8,9).Using condition 4: Bihari gave the highest rating in packaging and thus Bihari must have given a 9 rating in the packaging.Chirag gave the highest rating in Hygiene. In condition 3 it was mentioned that Chirag gave the same points for packaging and hygiene. Since 9 was rated by Bihari packaging it cannot be awarded by Chirag in packaging and hygiene. Since Chirag was awarded the highest in Hygiene. He must award 8 points in Hygiene and Packaging.Hence of the three possibilities among A, B, and C for Hygiene&nbsp;only B is the possible case with 8 as the maximum score.In condition 5 it was mentioned that everyone awarded Ravi between 5 and 7 in Behaviour. Unique maximum and minimum ratings in this parameter were given by Atal and Deepak respectively.Hence Atal must have awarded 7, Deepak 6, Bihari, and Chirag 6 each in Behaviour.The two possible cases are :Case 1 :<img src="https://lightyellow-stork-291267.hostingersite.com/wp-content/uploads/2025/11/image_Z5OM6BV.png" alt="image">Case 2 :<img src="https://lightyellow-stork-291267.hostingersite.com/wp-content/uploads/2025/11/image_DOQJCva.png" alt="image">The ratings awarded by Atal and Deepak in Packaging are among 5 and 7.The ratings awarded by Atal, Bihari, Deepak are among 5,6, and 7.Atal individual ranking in Packaging and Hygiene are the same. The same is true for Deepak.Since Atal and Deepak can give the ranking among 3 and 4 in Packaging as Bihari is first and Chirag is second in this parameter.They can rank 3 or 4 in the Hygiene parameter also. Hence Bihari must rate 7 points in Hygiene.In both the possibilities Bihari and Chirag award a total of 26 points. Hence he wins 40 because the total ratings are greater than 25 received from Bihari and Chirag.Since he gets a total of 120 in bonuses and tips. He must have 80 from Atal and Deepak.This is possible if he gets a tip of 30 ad 50 from them respectively.In case 1 irrespective of Atal standing at rank 3 or rank 4 in Hygiene and Packaging Atal total rating is greater than 25 which implies Ravi gets a tip from Atal but this is not a possible case because Ravi needs a total of Rs 80 from Atal and Deepak. From Atal if he gets Rs 20 as a bonus he cannot get a total of Rs 120 and hence this case fails.Hence case 1 fails.In case 2 there are two possibilities :Atal ranking 3 in both the parameters and Deepak 4th. Atal ranking 4th in both the parameters and Deepak 3rdIn the case where Atal ranks 3rd in Packaging and Hygiene the total score is 26 and is not a feasible case.Case - 2A<img src="https://lightyellow-stork-291267.hostingersite.com/wp-content/uploads/2025/11/image_WKcIuOa.png" alt="image">Case - 2B :<img src="https://lightyellow-stork-291267.hostingersite.com/wp-content/uploads/2025/11/image_Y6yaVvF.png" alt="image">Case - 2A&nbsp;fails because Atal's total rating is greater than 25 which should not be the case.Bihari&nbsp;and Chirag has given the highest ratings

Using condition 1 :Ravi had a total of 21 points in timeliness. 3 of the four customers among Atal, Bihari, Chirag, and Deepak gave him the same ratings. Atal gave the highest rating in timeliness in comparison with Bihari and Chirag. Hence he must have given the distinct rating.Using condition 2 :The possibilities are A - 9, B - 4, C - 4, D - 4.A - 6, B - 5, C - 5, D - 5.Ravi received a total of 29 points in the Packaging and for this, the possibility of the four scores are (5, 7, 8, 9) awarded by the four customers.In Hygiene the sum of the ratings awarded was 26. This could possibly be awarded by considering the following cases :A-(4,6,7,9) , B-( 5,6,7,8), C-(4,5,8,9).Using condition 4: Bihari gave the highest rating in packaging and thus Bihari must have given a 9 rating in the packaging.Chirag gave the highest rating in Hygiene. In condition 3 it was mentioned that Chirag gave the same points for packaging and hygiene. Since 9 was rated by Bihari packaging it cannot be awarded by Chirag in packaging and hygiene. Since Chirag was awarded the highest in Hygiene. He must award 8 points in Hygiene and Packaging.Hence of the three possibilities among A, B, and C for Hygiene&nbsp;only B is the possible case with 8 as the maximum score.In condition 5 it was mentioned that everyone awarded Ravi between 5 and 7 in Behaviour. Unique maximum and minimum ratings in this parameter were given by Atal and Deepak respectively.Hence Atal must have awarded 7, Deepak 6, Bihari, and Chirag 6 each in Behaviour.The two possible cases are :Case 1 :<img src="https://lightyellow-stork-291267.hostingersite.com/wp-content/uploads/2025/11/image_Z5OM6BV.png" alt="image">Case 2 :<img src="https://lightyellow-stork-291267.hostingersite.com/wp-content/uploads/2025/11/image_DOQJCva.png" alt="image">The ratings awarded by Atal and Deepak in Packaging are among 5 and 7.The ratings awarded by Atal, Bihari, Deepak are among 5,6, and 7.Atal individual ranking in Packaging and Hygiene are the same. The same is true for Deepak.Since Atal and Deepak can give the ranking among 3 and 4 in Packaging as Bihari is first and Chirag is second in this parameter.They can rank 3 or 4 in the Hygiene parameter also. Hence Bihari must rate 7 points in Hygiene.In both the possibilities Bihari and Chirag award a total of 26 points. Hence he wins 40 because the total ratings are greater than 25 received from Bihari and Chirag.Since he gets a total of 120 in bonuses and tips. He must have 80 from Atal and Deepak.This is possible if he gets a tip of 30 ad 50 from them respectively.In case 1 irrespective of Atal standing at rank 3 or rank 4 in Hygiene and Packaging Atal total rating is greater than 25 which implies Ravi gets a tip from Atal but this is not a possible case because Ravi needs a total of Rs 80 from Atal and Deepak. From Atal if he gets Rs 20 as a bonus he cannot get a total of Rs 120 and hence this case fails.Hence case 1 fails.In case 2 there are two possibilities :Atal ranking 3 in both the parameters and Deepak 4th. Atal ranking 4th in both the parameters and Deepak 3rdIn the case where Atal ranks 3rd in Packaging and Hygiene the total score is 26 and is not a feasible case.Case - 2A<img src="https://lightyellow-stork-291267.hostingersite.com/wp-content/uploads/2025/11/image_WKcIuOa.png" alt="image">Case - 2B :<img src="https://lightyellow-stork-291267.hostingersite.com/wp-content/uploads/2025/11/image_Y6yaVvF.png" alt="image">Case - 2A&nbsp;fails because Atal's total rating is greater than 25 which should not be the case.Atal has given a rating of 6 in timeliness

Using condition 1 :Ravi had a total of 21 points in timeliness. 3 of the four customers among Atal, Bihari, Chirag, and Deepak gave him the same ratings. Atal gave the highest rating in timeliness in comparison with Bihari and Chirag. Hence he must have given the distinct rating.Using condition 2 :The possibilities are A - 9, B - 4, C - 4, D - 4.A - 6, B - 5, C - 5, D - 5.Ravi received a total of 29 points in the Packaging and for this, the possibility of the four scores are (5, 7, 8, 9) awarded by the four customers.In Hygiene the sum of the ratings awarded was 26. This could possibly be awarded by considering the following cases :A-(4,6,7,9) , B-( 5,6,7,8), C-(4,5,8,9).Using condition 4: Bihari gave the highest rating in packaging and thus Bihari must have given a 9 rating in the packaging.Chirag gave the highest rating in Hygiene. In condition 3 it was mentioned that Chirag gave the same points for packaging and hygiene. Since 9 was rated by Bihari packaging it cannot be awarded by Chirag in packaging and hygiene. Since Chirag was awarded the highest in Hygiene. He must award 8 points in Hygiene and Packaging.Hence of the three possibilities among A, B, and C for Hygiene&nbsp;only B is the possible case with 8 as the maximum score.In condition 5 it was mentioned that everyone awarded Ravi between 5 and 7 in Behaviour. Unique maximum and minimum ratings in this parameter were given by Atal and Deepak respectively.Hence Atal must have awarded 7, Deepak 6, Bihari, and Chirag 6 each in Behaviour.The two possible cases are :Case 1 :<img src="https://lightyellow-stork-291267.hostingersite.com/wp-content/uploads/2025/11/image_Z5OM6BV.png" alt="image">Case 2 :<img src="https://lightyellow-stork-291267.hostingersite.com/wp-content/uploads/2025/11/image_DOQJCva.png" alt="image">The ratings awarded by Atal and Deepak in Packaging are among 5 and 7.The ratings awarded by Atal, Bihari, Deepak are among 5,6, and 7.Atal individual ranking in Packaging and Hygiene are the same. The same is true for Deepak.Since Atal and Deepak can give the ranking among 3 and 4 in Packaging as Bihari is first and Chirag is second in this parameter.They can rank 3 or 4 in the Hygiene parameter also. Hence Bihari must rate 7 points in Hygiene.In both the possibilities Bihari and Chirag award a total of 26 points. Hence he wins 40 because the total ratings are greater than 25 received from Bihari and Chirag.Since he gets a total of 120 in bonuses and tips. He must have 80 from Atal and Deepak.This is possible if he gets a tip of 30 ad 50 from them respectively.In case 1 irrespective of Atal standing at rank 3 or rank 4 in Hygiene and Packaging Atal total rating is greater than 25 which implies Ravi gets a tip from Atal but this is not a possible case because Ravi needs a total of Rs 80 from Atal and Deepak. From Atal if he gets Rs 20 as a bonus he cannot get a total of Rs 120 and hence this case fails.Hence case 1 fails.In case 2 there are two possibilities :Atal ranking 3 in both the parameters and Deepak 4th. Atal ranking 4th in both the parameters and Deepak 3rdIn the case where Atal ranks 3rd in Packaging and Hygiene the total score is 26 and is not a feasible case.Case - 2A<img src="https://lightyellow-stork-291267.hostingersite.com/wp-content/uploads/2025/11/image_WKcIuOa.png" alt="image">Case - 2B :<img src="https://lightyellow-stork-291267.hostingersite.com/wp-content/uploads/2025/11/image_Y6yaVvF.png" alt="image">Case - 2A&nbsp;fails because Atal's total rating is greater than 25 which should not be the case.Among Atal and Deepak, one of them gives a tip of 30 and the other gives a tip of 50. Hence 30 or 50 any case is possible

Using condition 1 :Ravi had a total of 21 points in timeliness. 3 of the four customers among Atal, Bihari, Chirag, and Deepak gave him the same ratings. Atal gave the highest rating in timeliness in comparison with Bihari and Chirag. Hence he must have given the distinct rating.Using condition 2 :The possibilities are A - 9, B - 4, C - 4, D - 4.A - 6, B - 5, C - 5, D - 5.Ravi received a total of 29 points in the Packaging and for this, the possibility of the four scores are (5, 7, 8, 9) awarded by the four customers.In Hygiene the sum of the ratings awarded was 26. This could possibly be awarded by considering the following cases :A-(4,6,7,9) , B-( 5,6,7,8), C-(4,5,8,9).Using condition 4: Bihari gave the highest rating in packaging and thus Bihari must have given a 9 rating in the packaging.Chirag gave the highest rating in Hygiene. In condition 3 it was mentioned that Chirag gave the same points for packaging and hygiene. Since 9 was rated by Bihari packaging it cannot be awarded by Chirag in packaging and hygiene. Since Chirag was awarded the highest in Hygiene. He must award 8 points in Hygiene and Packaging.Hence of the three possibilities among A, B, and C for Hygiene&nbsp;only B is the possible case with 8 as the maximum score.In condition 5 it was mentioned that everyone awarded Ravi between 5 and 7 in Behaviour. Unique maximum and minimum ratings in this parameter were given by Atal and Deepak respectively.Hence Atal must have awarded 7, Deepak 6, Bihari, and Chirag 6 each in Behaviour.The two possible cases are :Case 1 :<img src="https://lightyellow-stork-291267.hostingersite.com/wp-content/uploads/2025/11/image_Z5OM6BV.png" alt="image">Case 2 :<img src="https://lightyellow-stork-291267.hostingersite.com/wp-content/uploads/2025/11/image_DOQJCva.png" alt="image">The ratings awarded by Atal and Deepak in Packaging are among 5 and 7.The ratings awarded by Atal, Bihari, Deepak are among 5,6, and 7.Atal individual ranking in Packaging and Hygiene are the same. The same is true for Deepak.Since Atal and Deepak can give the ranking among 3 and 4 in Packaging as Bihari is first and Chirag is second in this parameter.They can rank 3 or 4 in the Hygiene parameter also. Hence Bihari must rate 7 points in Hygiene.In both the possibilities Bihari and Chirag award a total of 26 points. Hence he wins 40 because the total ratings are greater than 25 received from Bihari and Chirag.Since he gets a total of 120 in bonuses and tips. He must have 80 from Atal and Deepak.This is possible if he gets a tip of 30 ad 50 from them respectively.In case 1 irrespective of Atal standing at rank 3 or rank 4 in Hygiene and Packaging Atal total rating is greater than 25 which implies Ravi gets a tip from Atal but this is not a possible case because Ravi needs a total of Rs 80 from Atal and Deepak. From Atal if he gets Rs 20 as a bonus he cannot get a total of Rs 120 and hence this case fails.Hence case 1 fails.In case 2 there are two possibilities :Atal ranking 3 in both the parameters and Deepak 4th. Atal ranking 4th in both the parameters and Deepak 3rdIn the case where Atal ranks 3rd in Packaging and Hygiene the total score is 26 and is not a feasible case.Case - 2A<img src="https://lightyellow-stork-291267.hostingersite.com/wp-content/uploads/2025/11/image_WKcIuOa.png" alt="image">Case - 2B :<img src="https://lightyellow-stork-291267.hostingersite.com/wp-content/uploads/2025/11/image_Y6yaVvF.png" alt="image">Case - 2A&nbsp;fails because Atal's total rating is greater than 25 which should not be the case.Atal has given the maximum rating in Behaviour.

Using condition 1 :Ravi had a total of 21 points in timeliness. 3 of the four customers among Atal, Bihari, Chirag, and Deepak gave him the same ratings. Atal gave the highest rating in timeliness in comparison with Bihari and Chirag. Hence he must have given the distinct rating.Using condition 2 :The possibilities are A - 9, B - 4, C - 4, D - 4.A - 6, B - 5, C - 5, D - 5.Ravi received a total of 29 points in the Packaging and for this, the possibility of the four scores are (5, 7, 8, 9) awarded by the four customers.In Hygiene the sum of the ratings awarded was 26. This could possibly be awarded by considering the following cases :A-(4,6,7,9) , B-( 5,6,7,8), C-(4,5,8,9).Using condition 4: Bihari gave the highest rating in packaging and thus Bihari must have given a 9 rating in the packaging.Chirag gave the highest rating in Hygiene. In condition 3 it was mentioned that Chirag gave the same points for packaging and hygiene. Since 9 was rated by Bihari packaging it cannot be awarded by Chirag in packaging and hygiene. Since Chirag was awarded the highest in Hygiene. He must award 8 points in Hygiene and Packaging.Hence of the three possibilities among A, B, and C for Hygiene&nbsp;only B is the possible case with 8 as the maximum score.In condition 5 it was mentioned that everyone awarded Ravi between 5 and 7 in Behaviour. Unique maximum and minimum ratings in this parameter were given by Atal and Deepak respectively.Hence Atal must have awarded 7, Deepak 6, Bihari, and Chirag 6 each in Behaviour.The two possible cases are :Case 1 :<img src="https://lightyellow-stork-291267.hostingersite.com/wp-content/uploads/2025/11/image_Z5OM6BV.png" alt="image">Case 2 :<img src="https://lightyellow-stork-291267.hostingersite.com/wp-content/uploads/2025/11/image_DOQJCva.png" alt="image">The ratings awarded by Atal and Deepak in Packaging are among 5 and 7.The ratings awarded by Atal, Bihari, Deepak are among 5,6, and 7.Atal individual ranking in Packaging and Hygiene are the same. The same is true for Deepak.Since Atal and Deepak can give the ranking among 3 and 4 in Packaging as Bihari is first and Chirag is second in this parameter.They can rank 3 or 4 in the Hygiene parameter also. Hence Bihari must rate 7 points in Hygiene.In both the possibilities Bihari and Chirag award a total of 26 points. Hence he wins 40 because the total ratings are greater than 25 received from Bihari and Chirag.Since he gets a total of 120 in bonuses and tips. He must have 80 from Atal and Deepak.This is possible if he gets a tip of 30 ad 50 from them respectively.In case 1 irrespective of Atal standing at rank 3 or rank 4 in Hygiene and Packaging Atal total rating is greater than 25 which implies Ravi gets a tip from Atal but this is not a possible case because Ravi needs a total of Rs 80 from Atal and Deepak. From Atal if he gets Rs 20 as a bonus he cannot get a total of Rs 120 and hence this case fails.Hence case 1 fails.In case 2 there are two possibilities :Atal ranking 3 in both the parameters and Deepak 4th. Atal ranking 4th in both the parameters and Deepak 3rdIn the case where Atal ranks 3rd in Packaging and Hygiene the total score is 26 and is not a feasible case.Case - 2A<img src="https://lightyellow-stork-291267.hostingersite.com/wp-content/uploads/2025/11/image_WKcIuOa.png" alt="image">Case - 2B :<img src="https://lightyellow-stork-291267.hostingersite.com/wp-content/uploads/2025/11/image_Y6yaVvF.png" alt="image">Case - 2A&nbsp;fails because Atal's total rating is greater than 25 which should not be the case.Deepak gives a rating of 7 in Packaging.

cat 2021 Complete Paper Solution | DILR Slot 2

Instructions

Question 1.

Question 2.

Question 3.

Question 4.

Question 5.

Question 6.

Instructions

Question 7.

Question 8.

Question 9.

Question 10.

Instructions

Question 11.

Question 12.

Question 13.

Question 14.

Instructions

Question 15.

Question 16.

Question 17.

Question 18.

Question 19.

Question 20.

cat 2021 Complete Paper Solution | DILR Slot 2

Instructions

Question 1.

<div><p>What BEST can be said about object o8?</p></div>

Question 2.

<div><p>Who among the following envies someone else?</p></div>

Question 3.

<div><p>What is Amar's value for his own bundle?</p></div>

Question 4.

<div><p>Object o4 was given to</p></div>

Question 5.

<div><p>Object o5 was given to</p></div>

Question 6.

<div><p>What BEST can be said about the distribution of object o1?</p></div>

Instructions

Question 7.

<div><p>How many days between Sep 1 and Sep 14 (both inclusive) had no booking from this client considering all the above categories?</p></div>

Question 8.

<div><p>What was the average processing time of all orders in the categories which had only one type of ship mode?</p></div>

Question 9.

<div><p>The sequence of categories -- Art, Binders, Paper and Phones -- in decreasing order of average processing time of their orders in this period is:</p></div>

Question 10.

<div><p>Approximately what percentage of orders had a processing time of one day during the period Sep 1 to Sep 22 (both dates inclusive)?</p></div>

Instructions

Question 11.

<div><p>Who among the following was DEFINITELY NOT ranked first in his/her group?</p></div>

Question 12.

<div><p>Which of the following pairs must have played against each other in the championship?</p></div>

Question 13.

<div><p>Who won the championship?</p></div>

Question 14.

<div><p>Who among the following did NOT play against Chitra in the championship?</p></div>

Instructions

Question 15.

<div><p>What was the minimum rating that Ravi received from any customer in any parameter?</p></div>

Question 16.

<div><p>The COMPLETE list of customers who gave the maximum total rating points to Ravi is</p></div>

Question 17.

<div><p>What rating did Atal give on Timeliness?</p></div>

Question 18.

<div><p>What BEST can be concluded about the tip amount given by Deepak?</p></div>

Question 19.

<div><p>In which parameter did Atal give the maximum rating points to Ravi?</p></div>

Question 20.

<div><p>What rating did Deepak give on Packaging?</p></div>